(b-b^(1/3))/(b^(1/3)-1)

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Solution for (b-b^(1/3))/(b^(1/3)-1) equation: 


D( b )

b^(1/3)-1 = 0

b^(1/3)-1 = 0

b^(1/3)-1 = 0

1*b^(1/3) = 1 // : 1

b^(1/3) = 1

b^(1/3) = 1 // ^ 3

b = 1

b in (-oo:1) U (1:+oo)

(b-b^(1/3))/(b^(1/3)-1) = 0

b-b^(1/3) = 0

b^(1/3)*(b^(2/3)-1) = 0

1*b^(2/3) = 1 // : 1

b^(2/3) = 1

b^(2/3) = 1 // ^ 3

b^2 = 1 // ^ 1/2

abs(b) = 1

b = 1 or b = -1

b^(1/3)*(b-1)*(b+1) = 0

(b^(1/3)*(b-1)*(b+1))/(b^(1/3)-1) = 0

( b+1 )

b+1 = 0 // - 1

b = -1

( b-1 )

b-1 = 0 // + 1

b = 1

( b^(1/3) )

1*b^(1/3) = 0 // : 1

b^(1/3) = 0

b = 0

b in { 1} 

b in { -1, 0 }

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